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Go Math Answer Key

Texas Go Math Grade 5 Lesson 5.2 Answer Key Subtraction with Unequal Denominators

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 5.2 Answer Key Subtraction with Unequal Denominators.

Investigate

Mario fills a hummingbird feeder with \(\frac{3}{4}\) cup of sugar water on Friday. On Monday, Mario sees that \(\frac{1}{8}\) cup of sugar water is left. How much sugar water did the hummingbirds drink?

Materials: fraction strips; MathBoard

Texas Go Math Grade 5 Lesson 5.2 Answer Key 1

C. Record the difference, \(\frac{3}{4}\) – \(\frac{1}{8}\) = ___________

So, the hummingbirds drank _________ cup of sugar water. Answer:

C. Record the difference, \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)

So, the hummingbirds drank \(\frac{5}{8}\) cup of sugar water.

Math Talk Mathematical Processes

lesson 11 homework answer key 5.2

Draw Conclusions

lesson 11 homework answer key 5.2

Lesson 5.2 Answer Key 5th Grade Go Math Question 2. H.O.T. Explain whether you could have used fraction strips with any other denominator to find the difference. If so, what is the denominator? Answer: Unequal denominator Explanation: used fraction strips with any other denominator to find the difference. If so, that is called unequal denominator

Make Connections

Sometimes you can use different sets of same-denominator fraction strips to find the difference. All of the answers will be correct.

Solve. \(\frac{2}{3}\) – \(\frac{1}{6}\)

Texas Go Math Grade 5 Lesson 5.2 Answer Key 3

C. Find other fraction strips, all with the same denominator, that fit exactly under the difference \(\frac{2}{3}\) – \(\frac{1}{6}\). Draw the fraction strips you used. \(\frac{2}{3}\) – \(\frac{1}{6}\) = ____________

While each answer appears different, all of the answers can be simplified to _________. Answer:

lesson 11 homework answer key 5.2

While each answer appears different, all of the answers can be simplified to equal denominators

Which other fraction strips with the same denominator could fit exactly in the difference of \(\frac{2}{3}\) – \(\frac{1}{6}\)? Answer: \(\frac{3}{6}\) Explanation: fraction strips with the same denominator could fit exactly in the difference of \(\frac{2}{3}\) – \(\frac{1}{6}\) is \(\frac{3}{6}\)

Share and Show

Use fraction strips to find the difference. Write your answer in the simplest form.

Use fraction strips to find the difference. Write your answer in simplest form.

Question 3. \(\frac{3}{4}\) – \(\frac{1}{3}\) = _____________ Answer: \(\frac{3}{4}\) – \(\frac{1}{3}\) =\(\frac{9}{12}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 4. \(\frac{5}{6}\) – \(\frac{1}{2}\) = ______________ Answer: \(\frac{5}{6}\) – \(\frac{1}{2}\) = \(\frac{5}{6}\) – \(\frac{3}{6}\)= \(\frac{2}{6}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 5. \(\frac{3}{4}\) – \(\frac{7}{12}\) = ______________ Answer: \(\frac{3}{4}\) – \(\frac{7}{12}\) = \(\frac{9}{12}\) – \(\frac{7}{12}\) = \(\frac{2}{12}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Unlock the Problem

Texas Go Math Grade 5 Lesson 5.2 Answer Key 5

a. What problem are you being asked to solve? Answer: fractions with unequal denominators

b. How will you use the diagram to solve the problem? Answer: By calculating, Number of slices ate by number of slices are not eaten

c. Jason eats 1 of the whole pizza. How many slices does he eat? Answer: \(\frac{1}{8}\)

lesson 11 homework answer key 5.2

e. Write a fraction to represent the amount of pizza that is remaining. Answer: \(\frac{5}{8}\)

f. Fill in the bubble for the correct answer choice above. Answer: B

Lesson 5.2 Homework Answer Key 5th Grade Go Math Question 7. H.O.T. Explain how a model for \(\frac{3}{5}\) – \(\frac{1}{2}\) is different from a model for \(\frac{3}{5}\) – \(\frac{3}{10}\). Answer: \(\frac{3}{5}\) – \(\frac{1}{2}\) = \(\frac{6}{10}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\) \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{6}{10}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\) They both are same subtraction with unequal denominator both get the denominator same with numerator change

Daily Assessment Task

Fill in the bubble completely to show your answer.

Question 8. You are making cranberry lemonade for the Tastiest Beverage contest. You use \(\frac{3}{10}\) liter cranberry juice and \(\frac{1}{2}\) liter lemonade. You drink \(\frac{1}{10}\) liter, just to be sure that it tastes delicious! How much cranberry lemonade do you have left? (A) \(\frac{7}{10}\) liter (B) \(\frac{9}{10}\) liter (C) \(\frac{3}{11}\) liter (D) \(\frac{3}{10}\) liter Answer: A \(\frac{3}{10}\) + \(\frac{1}{2}\) = \(\frac{3}{10}\) + \(\frac{5}{10}\) = \(\frac{8}{10}\) \(\frac{8}{10}\) – \(\frac{1}{10}\) =\(\frac{7}{10}\)

Question 9. Use Diagrams Calvin used fraction strips correctly to model the difference of \(\frac{7}{12}\) – \(\frac{1}{3}\). Which of these describes his model? (A) seven \(\frac{1}{12}\) strips, one \(\frac{1}{3}\) strip, two \(\frac{1}{4}\) strips (B) seven \(\frac{1}{12}\) strips, one \(\frac{1}{3}\) strip, one \(\frac{1}{2}\) strip (C) seven \(\frac{1}{12}\) strips, two \(\frac{1}{6}\) strips, one \(\frac{1}{8}\) strip (D) seven \(\frac{1}{12}\) strips, one \(\frac{1}{3}\) strip, one \(\frac{1}{4}\) strip Answer:

Question 10. Multi-Step Bethany made her Apple Surprise drink by mixing \(\frac{1}{8}\) pint lemon juice, \(\frac{1}{8}\) pint grape juice, and \(\frac{4}{8}\) pint apple juice. She then drank \(\frac{1}{4}\) pint of the mixture. How much Apple Surprise was left? (A) \(\frac{1}{2}\) pint (B) \(\frac{1}{8}\) pint (C) \(\frac{1}{4}\) pint (D) \(\frac{3}{8}\) pint Answer: A \(\frac{1}{8}\) + \(\frac{1}{8}\) + \(\frac{4}{8}\) = \(\frac{6}{8}\) \(\frac{6}{8}\) – \(\frac{1}{4}\) = \(\frac{6}{8}\) – \(\frac{2}{8}\) = \(\frac{1}{2}\)

Texas Test Prep

Texas Go Math Grade 5 Lesson 5.2 Answer Key 6

Texas Go Math Grade 5 Lesson 5.2 Homework and Practice Answer Key

Texas Go Math Grade 5 Lesson 5.2 Answer Key 7

Question 3. \(\frac{1}{2}\) – \(\frac{1}{3}\) = _____________ Answer: \(\frac{1}{2}\) – \(\frac{1}{3}\) = \(\frac{3}{6}\) – \(\frac{2}{6}\) = \(\frac{1}{6}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 4. \(\frac{9}{10}\) – \(\frac{2}{5}\) = _____________ Answer: \(\frac{9}{10}\) – \(\frac{2}{5}\) = \(\frac{9}{10}\) – \(\frac{4}{10}\) = \(\frac{5}{10}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 5. \(\frac{11}{12}\) – \(\frac{3}{4}\) = _____________ Answer: \(\frac{11}{12}\) – \(\frac{3}{4}\) =  \(\frac{11}{12}\) – \(\frac{9}{12}\) =\(\frac{1}{6}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 6. \(\frac{5}{6}\) – \(\frac{1}{3}\) = _____________ Answer: Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 7. \(\frac{2}{3}\) – \(\frac{1}{12}\) = _____________ Answer: Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Go Math Lesson 5.2 Homework Answer Key Grade 5 Question 8. \(\frac{3}{4}\) – \(\frac{5}{12}\) = _____________ Answer: Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 9. \(\frac{9}{10}\) – \(\frac{1}{2}\) = _____________ Answer: Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 10. \(\frac{5}{8}\) – \(\frac{1}{2}\) = _____________ Answer: \(\frac{5}{8}\) – \(\frac{1}{2}\) = \(\frac{5}{8}\) – \(\frac{4}{8}\) = \(\frac{1}{8}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 11. \(\frac{3}{4}\) – \(\frac{2}{3}\) = _____________ Answer: \(\frac{3}{4}\) – \(\frac{2}{3}\) = \(\frac{9}{12}\) – \(\frac{8}{12}\) = \(\frac{1}{12}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Problem Solving

Question 12. Annette is making a fruit drink that calls for \(\frac{3}{4}\) cup of fresh lemon juice. She has \(\frac{1}{2}\) cup of lemon juice. How much more lemon juice does Annette need? Answer: \(\frac{3}{4}\) – \(\frac{1}{2}\) = \(\frac{3}{4}\)–\(\frac{2}{4}\) =  \(\frac{1}{4}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Question 13. Ramon needs to walk \(\frac{3}{4}\) mile to the bus stop. He has walked \(\frac{3}{8}\) mile so far. How much farther does Ramon need to walk to get to the bus stop? Answer: \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{6}{8}\) – \(\frac{3}{8}\) =\(\frac{3}{8}\) Explanation: The fraction with unequal denominators are subtracted to get the sum By doing them to equal denominators

Lesson Check

Fill In the bubble completely to show your answer.

Question 14. Matt spent \(\frac{1}{3}\) of the money in his pocket on a movie ticket. He spent \(\frac{1}{4}\) of the money on a snack. What fraction of his money is left? (A) \(\frac{7}{12}\) (B) \(\frac{5}{12}\) (C) \(\frac{1}{12}\) (D) \(\frac{1}{6}\) Answer: B Explanation: \(\frac{1}{3}\) + \(\frac{1}{4}\) = \(\frac{4}{12}\) + \(\frac{3}{12}\) = \(\frac{7}{12}\) 1 – \(\frac{7}{12}\) = \(\frac{5}{12}\) Matt spent \(\frac{1}{3}\) of the money in his pocket on a movie ticket. He spent \(\frac{1}{4}\) of the money on a snack. \(\frac{5}{12}\) fraction of his money is left.

Go Math Grade 5 Lesson 5.2 Homework Answer Key Question 15. Jabar used fraction strips to model the difference of \(\frac{7}{12}\) –\(\frac{1}{6}\) Which represents the difference? (A) seven \(\frac{1}{12}\) strips (B) one \(\frac{1}{12}\) strip (C) two \(\frac{1}{12}\) strips (D) five \(\frac{1}{12}\) strips Answer:  D \(\frac{7}{12}\) – \(\frac{1}{6}\) = \(\frac{7}{12}\) – \(\frac{2}{12}\) = \(\frac{5}{12}\) Explanation: Jabar used fraction strips to model the difference of \(\frac{7}{12}\) –\(\frac{1}{6}\)  represents the difference is five \(\frac{1}{12}\) strips

Question 16. Which fraction correctly completes the equation? \(\frac{3}{4}\) – _________ = \(\frac{1}{8}\) (A) \(\frac{7}{8}\) (B) \(\frac{1}{2}\) (C) \(\frac{5}{8}\) (D) \(\frac{1}{4}\) Answer: C Explanation: \(\frac{3}{4}\) – \(\frac{5}{8}\) = \(\frac{1}{8}\)

Question 17. Three friends share a pizza divided into eighths. If each person eats one slice, how many more slices must be eaten so that \(\frac{1}{2}\) of the pizza remains? (A) 1 (B) 2 (C) 3 (D) 4 Answer: A Explanation: Three friends share a pizza divided into eighths.\(\frac{3}{8}\) half of the pizza means 4 pieces If each person eats one slice, 1 more slices must be eaten so that \(\frac{1}{2}\) of the pizza remains

Question 18. Multi-Step Sara and Jon each ordered a medium pizza. Sara ate \(\frac{3}{8}\) of her pizza for lunch and \(\frac{1}{4}\) for a snack. Jon ate \(\frac{1}{2}\) of his pizza for lunch and \(\frac{1}{4}\) for a snack. How much more pizza did Jon eat? (A) \(\frac{1}{8}\) (B) \(\frac{1}{4}\) (C) \(\frac{1}{2}\) (D) \(\frac{1}{3}\) Answer: A Explanation: Sara and Jon each ordered a medium pizza. Sara ate \(\frac{3}{8}\) of her pizza for lunch and \(\frac{1}{4}\) for a snack. \(\frac{3}{8}\) + \(\frac{1}{4}\) = \(\frac{5}{8}\) Jon ate \(\frac{1}{2}\) of his pizza for lunch and \(\frac{1}{4}\) for a snack. \(\frac{1}{2}\) + \(\frac{1}{4}\) = \(\frac{3}{4}\) \(\frac{5}{8}\) – \(\frac{3}{4}\) = \(\frac{1}{8}\) Jon eat \(\frac{1}{8}\)

Question 19. Multi-Step On field day, \(\frac{1}{10}\) of the students in Mrs. Brown’s class competed in jumping events, \(\frac{3}{5}\) of the students competed in running events, and \(\frac{1}{10}\) competed in throwing events. What part of Mrs. Brown’s class did not compete in jumping, running, or throwing events? (A) \(\frac{1}{5}\) (B) \(\frac{7}{10}\) (C) \(\frac{2}{5}\) (D) \(\frac{4}{5}\) Answer: A Explanation: On field day, \(\frac{1}{10}\) of the students in Mrs. Brown’s class competed in jumping events, \(\frac{3}{5}\) of the students competed in running events, and \(\frac{1}{10}\) competed in throwing events. \(\frac{1}{10}\) + \(\frac{3}{5}\) + \(\frac{1}{10}\) = \(\frac{1}{10}\) + \(\frac{6}{10}\) + \(\frac{1}{10}\) = \(\frac{8}{10}\) – 1= \(\frac{1}{5}\)

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CCSS Math Answers

Eureka Math Grade 5 Module 2 Lesson 3 Answer Key

Engage ny eureka math 5th grade module 2 lesson 3 answer key, eureka math grade 5 module 2 lesson 3 problem set answer key.

Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 8 and 7, doubled

Answer: The sum of 8 and 7, doubled = 30.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-1

b. 4 times the sum of 14 and 26

Answer: The sum of 14 and 26, 4 times = 160.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-2

c. 3 times the difference between 37.5 and 24.5

Answer: The difference of 37.5 and 24.5, 3 times = 13.0.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-3

d. The sum of 3 sixteens and 2 nines

Answer: The sum of 3 sixteens and 2 nines = 30.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-4

e. The difference between 4 twenty-fives and 3 twenty-fives

Answer: The difference between 4 25 and 3 25 = 25.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-5

f. Triple the sum of 33 and 27

Answer: The sum of 33 and 27, 3 times = 180.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-6

Question 2. Write the numerical expressions in words. Then, solve.

Expression

Words

The Value of the Expression

a.       12 × (5 + 25) 12 times the sum of 5 and 25 12 x ( 30) = 360
b.      (62 – 12) × 11 11 times the difference of 62 and 12 (50) x 11 = 550
c.       (45 + 55) × 23 23 times the sum of 45 and 55 (100) x 23 = 2300
d.      (30 × 2) + (8 × 2) product of 30,2 and product of 8,2 (60) + (16) = 76

Answer: 360.

Explanation: In the above-given question, given that, 12 x ( 5 + 25). 12 x (30). 360.

Answer: 550.

Explanation: In the above-given question, given that, (62 – 12) × 11 50 x 11 = 550.

Answer: 2300.

Explanation: In the above-given question, given that, (45 + 55) × 23. 100 x 23. 2300.

Answer: 76.

Explanation: In the above-given question, given that, (30 × 2) + (8 × 2) 60 + 16. 76.

Eureka Math Grade 5 Module 2 Lesson 3 Problem Set Answer Key 1

Answer: 600 > 360.

Explanation: In the above-given question, given that, 24 x (20 + 5). 24 x 25. 600. (20 + 5) x 12. 30 x 12. 360. 600 > 360.

Answer: 487 > 513.

Explanation: In the above-given question, given that, 18 x 27. 487. 20 twenty-seven – 1 27. 540 – 27. 513. 487 < 513.

Answer: 171 = 171.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-7

Question 4. Mr. Huynh wrote the sum of 7 fifteens and 38 fifteens on the board. Draw a model, and write the correct expression.

Answer: The sum of 7 fifteens and 38 fifteens = 675.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-8

Question 5. Two students wrote the following numerical expressions. Angeline: (7 + 15) × (38 + 15) MeiLing: 15 × (7 + 38)   Are the students’ expressions equivalent to your answer in Problem 4? Explain your answer.

Answer: Yes, the student’s expressions equivalent.

Explanation: In the above-given question, given that, Angeline: (7 + 15) × (38 + 15) Meiling: 15 × (7 + 38)   105 + 570 = 675.

Question 6. A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. a. Write an expression to show how to find the total number of oranges ordered.

Answer: The total number of oranges ordered= 480.

Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480

b. Next week, Mr. Lee will double the number of boxes he orders. Write a new expression to represent the number of oranges in next week’s order.

Answer: The total number of oranges ordered= 960.

Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480 + 480 = 960

c. Evaluate your expression from Part (b) to find the total number of oranges ordered in both weeks.

Answer: The total number of oranges ordered in both weeks = 1440.

Explanation: In the above-given question, given that, 960 + 480 = 1440.

Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key

Question 1. Draw a model. Then, write the numerical expressions. a. The difference between 8 forty-sevens and 7 forty-sevens

Answer: The difference of 8 forty-sevens and 7 forty-sevens = 47.

Explanation: In the above-given question, given that, the difference of 8 forty sevens and 7 forty-sevens. 8 x 47 – 7 x 47. 376 – 329. 47

b. 6 times the sum of 12 and 8

Answer: The sum of 12 and 8, 6 times = 120.

Explanation: In the above-given question, given that, the sum of 12 and 8 is 120. 20 + 20 + 20 + 20 + 20 + 20 = 120. 12 + 8 = 20.

Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key 2

Answer: 4836 > 2028.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-9

Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key

Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 21 and 4, doubled b. 5 times the sum of 7 and 23 c. 2 times the difference between 49.5 and 37.5 d. The sum of 3 fifteens and 4 twos e. The difference between 9 thirty-sevens and 8 thirty-sevens f. Triple the sum of 45 and 55

Answer: The sum of 21 and 4, 2 times = 50.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-10

Answer: The sum of 7 and 23, 5 times = 150.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-11

Answer: 2 times the difference between 49.5 and 37.5 = 24.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-12

Answer: The sum of 3 fifteens and 4 twos = 53.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-13

Answer: The difference between 9 thirty-sevens and 8 thirty-sevens = 37.

Explanation: In the above-given question, given that, The difference between 9 thirty-sevens and 8 thirty-sevens 9 x 37 – 8 x 37. 333 – 296. 37.

Triple the sum of 45 and 55 = 300.

Explanation: In the above-given question, given that, Triple the sum of 45 and 55 45 + 55 = 100. 100 + 100 + 100 = 300.

Expression

Words

The Value of the Expression

a. 10 × (2.5 + 13.5) one hundred and sixty 10 x (16) = 160
b.  (98 – 78) × 11 two hundred and twenty (20) x 11 = 220
c. (71 + 29) × 26 two thousand six hundred (100) x 26 = 2600
d.  (50 × 2) + (15 × 2) one hundred and thirty (100) + 30 = 130

Answer: 160.

Explanation: In the above-given question, given that, 10 x ( 2.5 + 13.5). 10 x (16). 160.

Answer: 220.

Explanation: In the above-given question, given that, 11 x ( 98 – 78). 11 x (20). 220.

Answer: 2600.

Explanation: In the above-given question, given that, 26 x ( 71 + 29). 26 x (30). 2600.

Answer: 3000.

Explanation: In the above-given question, given that, (50 x 2) + ( 15 + 2). 100 x (30). 3000.

Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key 11

Answer: 3906 > 1438.

Explanation: In the above-given question, given that, 93 x ( 40 + 2). 93 x (42). 3906. (40 + 2) x 36 42 x 36. 1438. 3906 > 1438.

Answer: 1525 > 1475.

Explanation: In the above-given question, given that, 61 x ( 25). 1525. 60 twenty fives minus one twenty-five. 60  x 25 – 25. 1500 – 25. 1475. 1525 > 1475.

Question 4. Larry claims that (14 + 12) × (8 + 12) and (14 × 12) + (8 × 12) are equivalent because they have the same digits and the same operations. a. Is Larry correct? Explain your thinking.

Answer: Yes, Larry was not correct.

Explanation: In the above-given question, given that, Larry claims that (14 + 12) x (8 + 12) and (14 x 12) + (8 x 12). 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.

b. Which expression is greater? How much greater?

Answer: (14 + 12) x (8 + 12) is greater. 256 is greater.

Explanation: In the above-given question, given that, 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.

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IMAGES

  1. Eureka Math Grade 5 Lesson 11 Homework 5.2 Answer Key

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  2. Practice And Homework Lesson 11.5 Answer Key » Semanario Worksheet for

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  3. Go Math Grade 5 Practice And Homework Lesson 11.11 Answer Key

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  4. Solved Section 11.2 Homework Grade: 5.700002 (11 p Score:

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  5. Module 3 Lesson 11 Homework

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  6. Unveiling the Lesson 11.5 Answer Key: Unlocking the Secrets of Success

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  2. Module 6, Lesson 11 Homework Help

  3. Eureka Math Grade 3 Module 3 Lesson 11 Homework (Succeed)

  4. Eureka Math Grade 5 Module 1 Lesson 11 Homework (Succeed)

  5. Eureka Math Grade 1 Module 1 Lesson 11 Homework

  6. Eureka Math Grade 1 Module 5 Lesson 11 Homework (Succeed)

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  1. Eureka Math Grade 5 Module 5 Lesson 11 Answer Key

    Answer: 3/4 units long 1/2 units wide. Area = 3/8 units 2. Question 5. Colleen and Caroline each built a rectangle out of square tiles placed in 3 rows of 5. Colleen used tiles that measured 1 23 cm in length. Caroline used tiles that measured 3 13 cm in length. a.

  2. PDF Eureka Math

    2. Solve by drawing the area model and using the standard algorithm. 2,451 × 107 = 262, 257. 3. Solve using the standard algorithm. 7,302 × 408 = 2, 979, 216. 126. Lesson 11: Connect area models and the distributive property to partial products of the standard algorithm with renaming.

  3. Eureka Math Grade 5 Module 2 Lesson 11 Answer Key

    0.5 × 5 = 2.5. Answer: 3 x 3 = 9. Explanation: In the above-given question, given that, multiply. 3 x 3 = 9. Question 18. 0.05 × 5 = 025. Answer: 0.05 x 5 = 0.25. ... Eureka Math Grade 5 Module 2 Lesson 11 Homework Answer Key. Question 1. Estimate the product. Solve using the standard algorithm. Use the thought bubbles to show your thinking.

  4. PDF Grade 5 • Module 2

    11. 70,000 22. 84,000 33. 867,000 44. 129,000 Side B 1. 80 12. 600,000 23. 37,000 34. ... Lesson 4 Answer Key 5 •2 Lesson 4 Problem Set 1. a. (15 - 1) 29 and (10 29) - (6 29) 4. ... Lesson 4 Answer Key 5 •2 Homework 1. a. (30 19) - (7 29) and (40 - 2) 19 3.

  5. Engage NY // Eureka Math Grade 5 Module 2 Lesson 11 Homework

    Engage NY // Eureka Math Grade 5 Module 2 Lesson 11 Homework

  6. Eureka math grade 5 module 2 lesson 11 homework

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