lesson 3 homework 3.2 answer key

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• Core Connections Integrated I, 2013
• Core Connections Algebra 1, 2013
• Core Connections Geometry, 2013
• Core Connections Algebra 2, 2013
• Core Connections Integrated I, 2014
• Core Connections Integrated II, 2015
• Core Connections: Course 1
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• Core Connections Integrated III, 2015

Home > CCA > Chapter 5 > Lesson 5.3.2

Lesson 5.1.1, lesson 5.1.2, lesson 5.1.3, lesson 5.2.1, lesson 5.2.2, lesson 5.2.3, lesson 5.3.1, lesson 5.3.2, lesson 5.3.3.

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Texas Go Math Grade 5 Lesson 3.2 Answer Key Multiply Decimals and Whole Numbers

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 3.1 Answer Key Multiplication Patterns with Decimals.

Investigate

Giant tortoises move very slowly. They can travel a distance of about 0.17 mile in 1 hour, If a giant tortoise travels at the same speed, how far could it move in 4 hours? A. Complete the statement to describe the problem. I need to find how many total miles are in _0.17__ groups of _4__ • Write an expression to represent the problem. _0.17 X 4___

B. Use the decimal model to find the answer. • What does each small square in the decimal model represent?

C. Shade a group of ___ squares to represent the distance a giant tortoise can move in 1 hour.

D. Use a different color to shade each additional group of ___ squares until you have __ group of __ squares.

E. Record the total number of squares shaded. ___ squares So, the giant tortoise can move ___ mile in 4 hours.

E. Record the total number of squares shaded. __0.68_ squares So, the giant tortoise can move _0.68__ mile in 4 hours.

Explanation: A. Total number of miles are in 0.17 groups of 4, Wrote an expression to represent the problem 0.17 X 4, B. Used the decimal model to find the answer, Used small square in the decimal model represents, C. Shaded a group of 4 squares to represent the distance a giant tortoise can move in 1 hour. D. Used a different color to shade each additional group of  0.17 squares until you have 4 group of 0.17 squares.

E. Record the total number of squares shaded 0.68 squares So, the giant tortoise can move 0.68 mile in 4 hours.

Math talk Mathematical Process Explain how the model helps you determine if your answer is reasonable. Answer: Model helped easy way to represent decimal values with the whole,

Explanation: The model helped to determine the answer is reasonable as 4 blocks of 17 we get 17 X 4 68 hundredths places so 0.68.

Make connection

Step 1 Make 3 groups of 4 tenths and 6 hundredths. Remembering that a square or a flat is equal to 1. Drawn a quick picture to record your work.

Step 2 Combined the hundredths and renamed. There are _6__ hundredths. I will rename _6_ hundredths as _0.60__. In our quick picture, cross out the hundredths you renamed.

Step 3 Combined the tenths and renamed. There are _4_ tenths. I will rename _4_ tenths as _0.40__. In quick picture, cross out the tenths you renamed.

Step 4 Record the value shown by your completed quick picture. So, 3 × 0.46 = _1.38_

Share and Show

Math Talk Mathematical Processes Explain how renaming decimals is like renaming Whole numbers. Answer: Place values change,

Explanation: When whole numbers are renamed the decimal’s place values change from units to tenths, tens to hundredths.

Use the decimal model to find the product.

Step 2 Combined the hundredths and rename. There are 6 hundredths. I will rename _6__ hundredths as _0.60__. In our quick picture, cross out the hundredths you renamed.

Step 3 Recorded the value shown by your completed quick picture So, 5 × 0.06 = _0.30_

Explanation: Step 1 Making  5 groups of 3 tenths and 8  hundredths, Remembering that a square or a flat is equal to 1. Drawn a quick picture to record your work.

Step 2 Combined the tenths,hundredths and rename. There are 3 tenths and 8 hundredths, I will rename _3__ tenths and __8 __hundredths as _0.38__. In your quick picture, cross out the hundredths you renamed.

Step 3 Recorded the value shown by your completed quick picture So, 5 × 0.38 = _1.90_

Explanation: Step 1 Making  4 groups of 2 tenths and 4 hundredths, Remembering that a square or a flat is equal to 1. Drawn a quick picture to record your work.

Step 2 Combined the tenths and hundredths and rename. There are 2 tenths, 4 hundredths. I will rename 2 tenths, 4 hundredths as _0.24__. In your quick picture, cross out the hundredths you renamed.

Step 3 Recorded the value shown by your completed quick picture So, 4 × 0.24 = _0.96_

Step 2 Combined the tenths and hundredths and rename. There are 6 tenths, 2 hundredths. I will rename 6 tenths, 2 hundredths as _0.62__. In your quick picture, cross out the hundredths you renamed.

Step 3 Recorded the value shown by your completed quick picture So, 3 × 0.62 = _1.86_

Explanation: Step 1 Making 4 groups of 3 tenths and 2 hundredths, Remembering that a square or a flat is equal to 1. Drawn a quick picture to record your work.

Step 2 Combined the tenths and hundredths and rename. There are 3 tenths, 2 hundredths. I will rename 3 tenths, 2 hundredths as _1.28__. In your quick picture, cross out the hundredths you renamed.

Step 3 Recorded the value shown by your completed quick picture So, 4 × 0.32 = _1.28_

Problem Solving

Use the table for 6-8. Use quick pictures or base-ten blocks to help.

Explanation: Given each day a bobcat drinks about 3 times as much water as a Canada Goose drinks. Average amount each day Canada Goose drinks is 0.24 liters, Water does a bobcat drink in one day is 0.24 X  3 0.72

Explanation: Given Multi-Step River otters drink about 5 times as much water as a bald eagle drinks in a day. Average amount each day Bald Eagle drinks is 0.16 liters 5 X 0.16 = 0.80, Water does a River otter drink in three days is 3 X 0.80 0.80 X   3 2.40

Explanation: Given Math explained the amount of water that a cat drinks in 5 days is 5 X 0.15 = 0.75  liters.

Question 9. Compare the product of 0.46 and 3 with each of the factors. Which number has the greatest value? Explain how this is different than multiplying two whole numbers. Answer: The greatest values will be multiplying two whole numbers rather than multiplying decimal values,

Explanation: The product of 0.46 and 3 is 1 0.46 X   3 1.38 Factors of 0.4 is (0.1,0.4) or (0.2,0.2), Factors of 0.06 is (0.01,0.06) or (0.02, 0.03), Factors of 3 are (1,3), there are no common factors as we have whole numbers compared with tenths and hundredths, therefore, the greatest values will be multiplying two whole numbers rather than multiplying decimal values.

Daily Assessment Task

Fill in the bubble completely to show your answer.

Explanation: Given model represents 5 multiplied by 4 tenths, So matches with (A) 5 X 0.4.

Explanation: Given model represents 4 multiplied by 3 tenths and 1 hundredths giving the results as 4 X 0.31 = 0.31 X 4 1.24, So matches with (A) 4 X 0.31 = 1.24.

Explanation: Using Diagrams a quick picture to multiply 0.16 X  3 0.48 Now multiplying the result by 3 again, 0.48 X  3 0.24 1.20 1.44,  matches with (C).

Texas Test Prep

Lesson 3.2 Multiply Decimals by Whole Numbers Question 13. Jared has a parakeet that weighs 1.44 ounces. Susie has a Senegal parrot that weighs 3 times as much as Jared’s parakeet. How many ounces does Susie’s parrot weigh? (A) 0.32 ounce (B) 43.2 ounces (C) 4.32 ounces (D) 0.43 ounce Answer: (C) 4.32 ounces,

Explanation: Given Jared has a parakeet that weighs 1.44 ounces. Susie has a Senegal parrot that weighs 3 times as much as Jared’s parakeet. Number of ounces does Susie’s parrot weigh is 11 1.44 X  3 4.32 matches with (C) 4.32 ounces.

Texas Go Math Grade 5 Lesson 3.2 Homework and Practice Answer Key

Explanation: Given model represents 4 multiplied by 7 hundredths giving the results as 4 X 0.07 = 0.07 X  4 0.28, So 4 X 0.07 = 0.28.

Explanation: Given model represents 3 multiplied by 2 tenths and 1 hundredths giving the results as 3 X 0.21 = 0.21 X  3 0.63, So 3 X 0.63 = 0.63.

Find the product. Draw a quick picture.

Question 6. Lars walks his dog 4 times farther than Michelle walks her dog. Michelle walks her dog 0.23 mile. How far does Lars walk his dog? Answer: 0.92 Lars walk his dog,

Explanation: Lars walks his dog 4 times farther than Michelle walks her dog. Michelle walks her dog 0.23 mile. Far does Lars walk his dog is 0.23 X  4 0.92

Question 7. One day, Nat’s dog drank 3 times as much water as his cat. If his cat drank 0.83 liter of water, how many liters did his dog drink? Answer: 24.9 liter Nat’s dog drank water,

Explanation: One day, Nat’s dog drank 3 times as much water as his cat. If his cat drank 0.83 liter of water, Liters does his dog drank is 0.83 X  3 24.9 therefore, 24.9 liter Nat’s dog drank water.

Lesson Check

Explanation: Given model represents 5 multiplied by 1 tenth and 8 hundredths giving the results as 5 X 0.18 = 4 0.18 X  5 0.90, So 5 X 0.18 = 0.90.

Go Math Lesson 3.2 5th Grade Multiply Decimals Question 9. Sidney’s bag of popcorn weighs 1.89 ounces. Sam’s bag of popcorn weighs 4 times as much as Sidney’s. What is the weight of Sam’s bag of popcorn? (A) 0.756 ounce (B) 7.56 ounces (C) 75.6 ounces (D) 756 ounces Answer: (B) 7.56 ounces,

Explanation: Given Sidney’s bag of popcorn weighs 1.89 ounces. Sam’s bag of popcorn weighs 4 times as much as Sidney’s. So the weight of Sam’s bag of popcorn is 33 1.89 X  4 7.56  ounces which matches with (B).

Question 10. A beaker is filled with 0.23 liter of water. Leon fills another beaker with 3 times as much water. How much water is in Leon’s beaker? (A) 0.96 liter (B) 0.84 liter (C) 0.69 liter (D) 0.47 liter Answer: (C) 0.69 liter,

Explanation: Given a beaker is filled with 0.23 liter of water. Leon fills another beaker with 3 times as much water. So water is in Leon’s beaker is 0.23 X  3 0.69 liter which matches with (C).

Question 11. In a swimming race, Yvonne swam 0.18 mile. David swam 4 times as far as Yvonne. How far did David swim? (A) 2.2 miles (B) 0.22 mile (C) 7.2 miles (D) 0.72 mile Answer: (D) 0.72 mile,

Explanation: Given in a swimming race, Yvonne swam 0.18 mile. David swam 4 times as far as Yvonne. So far did David swim is 3 0.18 X  4  0.72 mile matches with (D).

Lesson 3.2 Answer Key 5th Grade Multiply Decimals Question 12. Multi-Step Carrie has 0.73 liters of juice in her pitcher. Sanji’s pitcher has 2 times as much juice as Carrie’s pitcher. Lee’s pitcher has 4 times as much juice as Carrie’s pitcher. Sanji and Lee pour all their juice into a large bowl. How much juice is in the bowl? (A) 1.46 liters (B) 4.38 liters (C) 2.92 liters (D) 5.11 liters Answer: (B) 4.38 liters,

Explanation: Given Multi-Step Carrie has 0.73 liters of juice in her pitcher. Sanji’s pitcher has 2 times as much juice as Carrie’s pitcher. So Sanji’s pitcher has 2 X 0.73 = 1.46 liters, Lee’s pitcher has 4 times as much juice as Carrie’s pitcher. So Lee’s pitcher has 4 X 0.73 = 2.92 liters, As Sanji and Lee pour all their juice into a large bowl. Juice is in the bowl is 1.46 + 2.92 = 4.38 liters matches with (B).

Question 13. Multi-Step Justin and Hayden are playing a number game. Justin’s number is the product of 4 × 0.06. Hayden’s number 0.04 less than the product of Justin’s number and 4. What is Hayden’s number? (A) 0.92 (B) 0.96 (C) 0.60 (D) 1.0 Answer: (A) 0.92,

Explanation: Given Justin and Hayden are playing a number game. Justin’s number is the product of 4 × 0.06. Hayden’s number 0.04 less than the product of Justin’s number and 4, Justin’s number is 4 X 0.06 = 0.24, Hayden’s number is (4 X 0.24) – 0.04 = 0.96 – 0.04 = 0.92 matches with (A).

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Eureka Math Grade 3 Module 2 Lesson 21 Answer Key

Engage ny eureka math 3rd grade module 2 lesson 21 answer key.

Answer: Estimate: 91g+58g ≈ 90g+60g=150g Actual:91g+58g=149g

b. Estimate, and then find the difference between the weight of the beans and rice. Estimate: ________ – ________ ≈ ________ – ________ = _________ Actual: ________ – ________ = _________

Answer: My answers are reasonable because 150g is only 1 more than 149g and 30g is only 3 less than 33g.

Question 2. Measure the lengths of the three pieces of yarn. a. Estimate the total length of Yarn A and Yarn C. Then, find the actual total length.

b. Subtract to estimate the difference between the t otal length  of Yarns A and C, and the length of Yarn B. Then, find the actual difference. Model the problem with a tape diagram.

b. Estimate to find the difference between the amount of water in Containers D and E. Then, find the actual difference. Model the problem with a tape diagram.

Question 4. Shane watches a movie in the theater that is 115 minutes long, including the trailers. The chart to the right shows the length in minutes of each trailer. a. Find the total number of minutes for all 5 trailers.

Answer: The total is 5+4+3+5+4=21 minutes

b. Estimate to find the length of the movie without trailers. Then, find the actual length of the movie by calculating the difference between 115 minutes and the total minutes of trailers.

Answer: 115min – 21 min    120-20=100min 115min-21min=94min The estimated length is 100 minutes and the actual length is 94minutes.

c. Is your answer reasonable? Explain why.

Answer: Yes, it is reasonable because 94minutes is close to 100minutes.

Eureka Math Grade 3 Module 2 Lesson 21 Exit Ticket Answer Key

Rogelio drinks water at every meal. At breakfast, he drinks 237 milliliters. At lunch, he drinks 300 milliliters. At dinner, he drinks 177 milliliters. a. Estimate the total amount of water Rogelio drinks. Then, find the actual amount of water he drinks at all three meals.

Answer: Estimate: 237 ml  ≈ 200 ml 300 ml ≈ 300 ml 177 ml ≈ 177 ml 200+300+177=677ml About 677ml amount of water Rogelio drinks

b. Estimate how much more water Rogelio drinks at lunch than at dinner. Then, find how much more water Rogelio actually drinks at lunch than at dinner.

Answer: Estimate: 300 ml ≈ 300 ml 177 ml ≈ 200 ml 300-200=100 ml About 100ml more water Rogelio drinks at lunch than at dinner

Eureka Math Grade 3 Module 2 Lesson 21 Homework Answer Key

Question 1. There are 153 milliliters of juice in 1 carton. A three-pack of juice boxes contains a total of 459 milliliters. Estimate, and then find the actual total amount of juice in 1 carton and in a three-pack of juice boxes. 153 mL + 459 mL ≈ ______ + ______ =______ 153 mL + 459 mL = ______

b. Estimate, and then find the actual difference between the amount in 1 carton and in a three-pack of juice boxes. 459 mL − 153 mL ≈ ______ − ______ = ______ 459 mL − 153 mL = ______

c. Are your answers reasonable? Why? Answer: No, my answer in addition is not reasonable as it is not close to the actual answer. Yes, my answers in subtraction is reasonable as it is close to the actual answer.

Question 2. Mr. Williams owns a gas station. He sells 367 liters of gas in the morning, 300 liters of gas in the afternoon, and 219 liters of gas in the evening. a. Estimate, and then find the actual total amount of gas he sells in one day.

Answer: Estimate: 367 L + 300 L + 219 L ≈ 400 L + 300 L + 200 L = 900 L The estimated total amount of gas Mr.Williams sells in one day is 900L.

b. Estimate, and then find the actual difference between the amount of gas Mr. Williams sells in the morning and the amount he sells in the evening.

Answer: 367 L – 219 L ≈ 400 L – 200 L = 200 L The estimated difference between the amount of gas Mr. Williams sells in the morning and the amount he sells in the evening

Question 3. The Blue Team runs a relay. The chart shows the time, in minutes, that each team member spends running. a. How many minutes does it take the Blue Team to run the relay?

Answer: The Blue Team took 28 minutes to run the relay.

b. It takes the Red Team 37 minutes to run the relay. Estimate, and then find the actual difference in time between the two teams.

Answer: Estimate: 37 min ≈ 40 min 26 min ≈ 30min 40-30=10min The estimated difference in time between the two teams is 10 minutes

Question 4. The lengths of three banners are shown to the right. a. Estimate, and then find the actual total length of Banner A and Banner C.

Answer: Estimate: 437 cm + 332 cm ≈ 400 L + 300 L =700 L The estimate total length of Banner A and Banner C = 700 cm.

b. Estimate, and then find the actual difference in length between Banner B and the combined length of Banner A and Banner C. Model the problem with a tape diagram.

Answer: Estimate: (437 cm+332 cm) – 457 L ≈ (400+300cm) – 400 L = 700 cm – 400 L =300 L The estimated difference in length between Banner B and the combined length of Banner A and Banner C is 300 cm

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